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x^2+6x+4=2x-4
We move all terms to the left:
x^2+6x+4-(2x-4)=0
We get rid of parentheses
x^2+6x-2x+4+4=0
We add all the numbers together, and all the variables
x^2+4x+8=0
a = 1; b = 4; c = +8;
Δ = b2-4ac
Δ = 42-4·1·8
Δ = -16
Delta is less than zero, so there is no solution for the equation
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